y=mx+b - Line Eqaution, Slope - m=(y2-y1)/(x2-x1), Domain y=√(f(x)) - x≥0 [0,∞), domain y=ln(f(x))  - x>0 (0,∞), Not Colinear - A(1,2) B(2,5) C(4,8) mab=1 | mac= -2/3, domain y=Log(f(x))  - x>0 , (0,∞), Function  - x-point are not repeated through V.L.T, Parallel Lines  - m1 = m2 L1 || L2, 1-1 Function (one to one) - y-point & x-point are not repeated through H.L.T & V.L.T, Perpendicular Lines - m1 x m2 = -1 , Colinear - A(2,1) B(0,2) C(4,0) mab=-1/2 | mac=1/-2, |2x+6|≥4 - Solution set: [-5 ≥ x ≥ -1], y=x2 - The Graph is Not Function !, y=x3 - The Graph is Function !, f(x)=x3+4 inverse to ? - f-1(x)= ( x-4 )1/3 , f(x)= x3 - 2 Inverse to ? - f-1(x)= (x+2)1/3, Yes - F(x)= ex Are inverse to F-1(x)= ln(x), No - F(x)= Log(x) Are inverse to F-1(x)= sin(x), y= 4sin-1(2x-3)-π (Range) - The Range -3π ≤ y ≤ π, y= 2cos(π/3 x -π)-1(Domain) - The Domain ( -∞ , ∞ ), y= 4sin-1(2x-3)-π (Domain) - The Domain 1 ≤ x ≤ 2, y= 2cos(π/3 x-π )-1 (Range) - The Range ( -3 , 1 ),

Preliminaries of calculus

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