3x+4x−2+5 - 7x+3, 2(x+3) - 2x+6, x2 + 5x - x(x+5), 2a+3b−a+4b - a+7b, Substitute x=2 into: 4x2−3x+1 - 11, Inverse of multiplying by 5 - Divide by 5, BIDMAS: 3+2×(5−1)2 - 35, (x+2)(x+3) - x2+5x+6, Factorise completely: 3x2+6x - 3x(x+2), (2x+6​)╱2 - x+3,

Leaderboard

Visual style

Options

Switch template

Continue editing: ?