1) k = 5, k = -3 a) ∣ 3k - 3 ∣ = 12 b) ∣ 4k - 6 ∣ = 18 c) ∣ 8k + 4 ∣ = 76 d) ∣ 6 + 5k ∣ = 14 2) k = 6, x = -3 a) ∣ 8k + 4 ∣ = 76 b) ∣ 3k - 3 ∣ = 12 c) ∣ 6 + 5k ∣ = 14 d) ∣ 4k - 6 ∣ = 18 3) In order to solve an absolute value equation... a) you must cross your fingers and hope you make a good guess. b) you must isolate the absolute value and set it equal to both the positive and negative value on the opposite side, resulting in 2 solutions. c) you use the same steps as any equation. 4) The distance from zero on a number line is called _____________________________. a) compound inequalities b) literal equations c) absolute value d) distance formula 5) k = 8/5, k = - 4 a) ∣ 8k + 4 ∣ = 76 b) ∣ 3k - 3 ∣ = 12 c) ∣ 4k - 6 ∣ = 18 d) ∣ 6 + 5k ∣ = 14

Absolute Value Equations Practice

Leaderboard

Visual style

Options

Switch template

Continue editing: ?