(15+9)·6, 15·6+9·6, 15·6+9, 15+9·6, 15·9·6, 47·18-17·18, (47-18)·17, (47+18)·17, (47-17)·18, (47·17)·18, Apskaičiuokite reiškinio 48·8+52·8 reikšmę, taikydami daugybos skirstymo dėsnį., (48+52)·8=100·8=800, (48+8)·52=56·52=2912, (52+8)·48=60·48=2880, (48+52)·8=90·8=7200, Palyginkite reiškinių (87-29)·31 ir 87·31-29·31 reikšmes., >, <, =, Kas turi būti įrašyta žvaigždelės vietoje: 39·*+61·*=(39+61)·6, 6, 39, 61, 5, 100, Kas turi būti įrašyta žvaigždelės vietoje: (12+25)·3=12·*+25·3, 12, 25, 3, 7, Kas turi būti daugtaškio vietoje: (25−8)·5=...·5−8·5, 5, 8, 25, 13, Kaip galime lengviau apskaičiuoti sandaugą 49·7, (40+9)·7, (50-1)·7, (44+5)·7, (13+6)·7, Pritaikykite daugybos skirstymo dėsnį: 7·12+20·12 =, (7+12)·20, (7+20)·12, (12+20)·7, (7·12)·20, Kaip galime lengviau apskaičiuoti sandaugą 102·9, (50+52)·9=50·9+52·9=, (100+2)·9=100·9+2·9=, (200-98)·9=200·9-98·9=, (80+22)·9=80·9+22·9=
0%
Daugybos skirstomumo dėsnis
Share
Share
Share
by
U95404979
5 kl.
Matematika
Edit Content
Print
Embed
More
Assignments
Leaderboard
Show more
Show less
This leaderboard is currently private. Click
Share
to make it public.
This leaderboard has been disabled by the resource owner.
This leaderboard is disabled as your options are different to the resource owner.
Revert Options
Quiz
is an open-ended template. It does not generate scores for a leaderboard.
Log in required
Visual style
Fonts
Subscription required
Options
Switch template
Show all
More formats will appear as you play the activity.
Open results
Copy link
QR code
Delete
Continue editing:
?
