Tạo các bài học thú vị hơn nhanh hơn
Vietnamese
Trang chủ Tính năng Giá của các gói đăng ký  Cộng đồng
1) What should we do when we do implicit differentiation? a) write a dy/dx at the back after we differentiate y term b) dy/dx = dy/dt divided by dx/dt c) bottom part of dy/dx , equate to 0 d) dy/dx = dx/dt divided by dy/dt e) use y - y1   = m ( x - x1 ) f) top part of dy/dx , equate to 0 2) What should we do when we do parametric differentiation? a) write a dy/dx at the back after we differentiate y term b) find dx/dt, dy/dt, lastly, dy/dx = (dy/dt )divided by (dx/dt) c) bottom part of dy/dx , equate to 0 d) find dy/dt, dy/dx, lastly, dy/dt = (dy/dx )divided by (dx/dt) e) find dx/dt, dy/dt, lastly, dy/dx = (dx/dt )divided by (dy/dt) f) top part of dy/dx , equate to 0 3) What should we do when the question tells us the tangent is parallel to x - axis? a) write a dy/dx at the back after we differentiate y term b) dy/dx = dy/dt divided by dx/dt c) bottom part of dy/dx , equate to 0 d) dy/dx = dx/dt divided by dy/dt e) use y - y1   = m ( x - x1 ) f) top part of dy/dx , equate to 0 4) What should we do when the question tells us the tangent is parallel to y - axis? a) write a dy/dx at the back after we differentiate y term b) dy/dx = dy/dt divided by dx/dt c) bottom part of dy/dx , equate to 0 d) dy/dx = dx/dt divided by dy/dt e) use y - y1   = m ( x - x1 ) f) top part of dy/dx , equate to 0 5) What should we do we want to find equation of tangent? a) write a dy/dx at the back after we differentiate y term b) dy/dx = dy/dt divided by dx/dt c) bottom part of dy/dx , equate to 0 d) dy/dx = dx/dt divided by dy/dt e) gradient of tangent is dy/dx, use y - y1   = m ( x - x1 ) f) top part of dy/dx , equate to 0 6) dy/dx = 3. Which is true? a) m tangent = 3, m normal = - 3 b) m tangent = 3, m normal = - 1/3 c) m tangent = - 3, m normal = 1/ 3 d) m tangent = - 3, m normal = - 1/3 e) m tangent = 3, m normal = 3 f) m tangent = 1/ 3, m normal = - 3 7) d/dx ( x3 ln 2y ) a) 3x 2 ln 2y + (1/2y) x3 b) 3x 2 ln 2y + (1/y) x3 c) 3x 2 ln 2y + (1/y) 2x2 d) x 3 ln 2y + (1/y) 2x3 e) 3x 2 ln 2y + (1/2y) x2 f) Too difficult

Differentiation - Recap 2

bởi
Nhiều hơn

Chuyển đổi mẫu

Phong cách trực quan

Tùy chọn

Bảng xếp hạng

Mê cung truy đuổi là một mẫu kết thúc mở. Mẫu này không tạo điểm số cho bảng xếp hạng.
Bạn có muốn khôi phục tự động lưu: không?